- The wait-for graph scheme is not applicable to a resource-allocation system with multiple instances of each resource type.
- We turn now to a deadlock-detection algorithm that is applicable to such a system. The algorithm employs several time-varying data structures:
- Available. A vector of length indicates the number of available resources of each type.
- Allocation. An
matrix defines the number of resources of each type currently allocated to each process.
- Request. An
matrix indicates the current request of each process.
- If
equals , then process is requesting more instances of resource type .
- The detection. algorithm described here simply investigates every possible allocation sequence for the processes that remain to be completed.
- Let and be vectors of length and , respectively. Initialize
. For
, if
, then
; otherwise,
.
- Find an index such that both
- a.
-
- b.
-
If no such exists, go to step 4.
-
Go to step 2.
- If
, for some
, then the system is in a deadlocked state. Moreover, if
, then process is deadlocked.
- Consider a system with five processes through and three resource types , , and .
- Resource type has seven instances,
- Resource type has two instances,
- Resource type has six instances.
- Suppose that, at time , we have the following resource-allocation state:
|
Allocation |
Request |
Available |
|
|
|
|
|
010 |
000 |
000 |
|
200 |
202 |
|
|
303 |
000 |
|
|
211 |
100 |
|
|
002 |
002 |
|
- If the algorithm is executed, it will be found that the sequence
results in
for all .
- Suppose now that process makes one additional request for an instance of type .
- Although we can reclaim the resources held by process , the number of available resources is not sufficient to fulfill the requests of the other processes. Thus, a deadlock exists, consisting of processes
, and .
Cem Ozdogan
2011-02-14